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Foundations
hard
0:00.0
Evaluate
∑
n
=
1
4
(
2
n
−
n
)
\sum_{n=1}^{4} (2^n - n)
∑
n
=
1
4
(
2
n
−
n
)
.
A
22
22
22
B
26
26
26
C
20
20
20
D
24
24
24
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