Evaluate the domain of f(x)=1x2−5x+6f(x) = \frac{1}{\sqrt{x^2 - 5x + 6}}f(x)=x2−5x+61.
(2,3)(2, 3)(2,3)
[2,3][2, 3][2,3]
R∖{2,3}\mathbb{R} \setminus \{2, 3\}R∖{2,3}
(−∞,2)∪(3,∞)(-\infty, 2) \cup (3, \infty)(−∞,2)∪(3,∞)