Evaluate the following expression given x=2x=2x=2 and y=3y=3y=3: (x−2y3x3y−2)−1\left(\frac{x^{-2}y^3}{x^3y^{-2}}\right)^{-1}(x3y−2x−2y3)−1
32243\frac{32}{243}24332
253−5\frac{2^{5}}{3^{-5}}3−525
2−535\frac{2^{-5}}{3^{5}}352−5
24332\frac{243}{32}32243