Evaluate ddx[sin3(x)]\frac{d}{dx}[\sin^3(x)]dxd[sin3(x)].
3sin2(x)cos(x)3\sin^2(x)\cos(x)3sin2(x)cos(x)
3sin2(x)3\sin^2(x)3sin2(x)
cos3(x)\cos^3(x)cos3(x)
−3sin2(x)cos(x)-3\sin^2(x)\cos(x)−3sin2(x)cos(x)