Events AAA and BBB satisfy P(A)=0.4P(A)=0.4P(A)=0.4, P(B)=0.5P(B)=0.5P(B)=0.5, P(A∪B)=0.7P(A\cup B)=0.7P(A∪B)=0.7. Are AAA and BBB independent?
Yes — P(A∩B)=P(A)⋅P(B)=0.2P(A\cap B) = P(A)\cdot P(B) = 0.2P(A∩B)=P(A)⋅P(B)=0.2
No — P(A∩B)≠P(A)⋅P(B)P(A\cap B) \neq P(A)\cdot P(B)P(A∩B)=P(A)⋅P(B)
Cannot be determined from the given information
Yes — because P(A∪B)<1P(A\cup B) < 1P(A∪B)<1