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Recurrence Relations
easy
0:00.0
Find
a
2
a_2
a
2
for
a
n
=
n
⋅
a
n
−
1
a_n = n \cdot a_{n-1}
a
n
=
n
⋅
a
n
−
1
with
a
1
=
1
a_1 = 1
a
1
=
1
.
A
1
B
2
C
3
D
4
Submit Answer