Find all nnn such that n2+1n^2 + 1n2+1 is divisible by 555.
n≡2(mod5)n \equiv 2 \pmod{5}n≡2(mod5)
n≡1(mod5)n \equiv 1 \pmod{5}n≡1(mod5)
n≡3(mod5)n \equiv 3 \pmod{5}n≡3(mod5)
n≡4(mod5)n \equiv 4 \pmod{5}n≡4(mod5)