Find all x∈[0,π]x \in [0, \pi]x∈[0,π] such that cos2x=sin2x\cos^2 x = \sin^2 xcos2x=sin2x.
π/4\pi/4π/4
π/4,3π/4\pi/4, 3\pi/4π/4,3π/4
π/2\pi/2π/2
0,π0, \pi0,π