Find an eigenvector for λ=1\lambda = 1λ=1 of A=(2−110)A = \begin{pmatrix} 2 & -1 \\ 1 & 0 \end{pmatrix}A=(21−10)
(11)\begin{pmatrix} 1 \\ 1 \end{pmatrix}(11)
(1−1)\begin{pmatrix} 1 \\ -1 \end{pmatrix}(1−1)
(01)\begin{pmatrix} 0 \\ 1 \end{pmatrix}(01)
(21)\begin{pmatrix} 2 \\ 1 \end{pmatrix}(21)