Find f−1(x)f^{-1}(x)f−1(x) if f(x)=2x3−1f(x) = 2x^3 - 1f(x)=2x3−1.
f−1(x)=x+123f^{-1}(x) = \sqrt[3]{\frac{x+1}{2}}f−1(x)=32x+1
f−1(x)=x3+12f^{-1}(x) = \frac{\sqrt[3]{x}+1}{2}f−1(x)=23x+1
f−1(x)=2x+13f^{-1}(x) = \sqrt[3]{2x+1}f−1(x)=32x+1
f−1(x)=x2+13f^{-1}(x) = \sqrt[3]{\frac{x}{2} + 1}f−1(x)=32x+1