Find f−1(x)f^{-1}(x)f−1(x) if f(x)=\ac2x−14f(x) = \ac{2x - 1}{4}f(x)=\ac2x−14.
f−1(x)=4x+1f^{-1}(x) = 4x + 1f−1(x)=4x+1
f−1(x)=\ac4x−12f^{-1}(x) = \ac{4x-1}{2}f−1(x)=\ac4x−12
f−1(x)=2x+4f^{-1}(x) = 2x + 4f−1(x)=2x+4
f−1(x)=\ac4x+12f^{-1}(x) = \ac{4x+1}{2}f−1(x)=\ac4x+12