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Derivatives
hard
0:00.0
Find
f
′
(
0
)
f'(0)
f
′
(
0
)
for
f
(
x
)
=
ln
(
1
+
e
x
)
f(x) = \ln(1 + e^x)
f
(
x
)
=
ln
(
1
+
e
x
)
.
A
e
e
e
B
0
0
0
C
1
1
1
D
1
/
2
1/2
1/2
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