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Derivatives
hard
0:00.0
Find
f
′
′
(
0
)
f''(0)
f
′′
(
0
)
for
f
(
x
)
=
ln
(
x
2
+
1
)
f(x) = \ln(x^2+1)
f
(
x
)
=
ln
(
x
2
+
1
)
.
A
0
0
0
B
2
2
2
C
−
2
-2
−
2
D
1
1
1
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