Find ddx[lnxx]\frac{d}{dx}\left[\frac{\ln x}{x}\right]dxd[xlnx].
1−lnxx2\frac{1-\ln x}{x^2}x21−lnx
1x2\frac{1}{x^2}x21
lnx−1x2\frac{\ln x - 1}{x^2}x2lnx−1
1+lnxx2\frac{1+\ln x}{x^2}x21+lnx