Find ddx[sin−1(x2)]\frac{d}{dx}[\sin^{-1}(x^2)]dxd[sin−1(x2)].
2x1−x4\frac{2x}{\sqrt{1-x^4}}1−x42x
11−x4\frac{1}{\sqrt{1-x^4}}1−x41
2x1−x2\frac{2x}{\sqrt{1-x^2}}1−x22x
x1−x4\frac{x}{ \sqrt{1-x^4}}1−x4x