Find ddx[sin2(x2)]\frac{d}{dx}[\sin^2(x^2)]dxd[sin2(x2)].
4xsin(x2)cos(x2)4x\sin(x^2)\cos(x^2)4xsin(x2)cos(x2)
2sin(x2)cos(x2)2\sin(x^2)\cos(x^2)2sin(x2)cos(x2)
2sin(x2)2\sin(x^2)2sin(x2)
4xsin(x2)4x\sin(x^2)4xsin(x2)