Find dydx\frac{dy}{dx}dxdy for y=x+2x−1y = \frac{x+2}{x-1}y=x−1x+2 using the quotient rule.
1(x−1)2\frac{1}{(x-1)^2}(x−1)21
−3(x−1)2\frac{-3}{(x-1)^2}(x−1)2−3
2x−1(x−1)2\frac{2x-1}{(x-1)^2}(x−1)22x−1
3(x−1)2\frac{3}{(x-1)^2}(x−1)23