Find dydx\frac{dy}{dx}dxdy for y=x+xy = \sqrt{x+\sqrt{x}}y=x+x.
12x+x\frac{1}{2\sqrt{x+\sqrt{x}}}2x+x1
12x\frac{1}{2\sqrt{x}}2x1
2x+14xx+x\frac{2\sqrt{x}+1}{4\sqrt{x}\sqrt{x+\sqrt{x}}}4xx+x2x+1
1+1/(2x)2x+x\frac{1+1/(2\sqrt{x})}{2\sqrt{x+\sqrt{x}}}2x+x1+1/(2x)