Find f′(x)f'(x)f′(x) for f(x)=3x2+2x3f(x) = \frac{3}{x^2} + \frac{2}{x^3}f(x)=x23+x32.
−6x3−6x4-\frac{6}{x^3} - \frac{6}{x^4}−x36−x46
6x3+6x4\frac{6}{x^3} + \frac{6}{x^4}x36+x46
−3x3−2x4-\frac{3}{x^3} - \frac{2}{x^4}−x33−x42
6x+6x2\frac{6}{x} + \frac{6}{x^2}x6+x26