Find f′(x)f'(x)f′(x) for f(x)=exx2+1f(x) = \frac{e^x}{x^2 + 1}f(x)=x2+1ex.
ex(x2−2x+1)(x2+1)2\frac{e^x(x^2 - 2x + 1)}{(x^2+1)^2}(x2+1)2ex(x2−2x+1)
ex(x−1)2(x2+1)2\frac{e^x(x-1)^2}{(x^2+1)^2}(x2+1)2ex(x−1)2
ex(x2+1)−2xex(x2+1)2\frac{e^x(x^2+1) - 2xe^x}{(x^2+1)^2}(x2+1)2ex(x2+1)−2xex
Both (a) and (c) are equivalent