Find ∫(x+1)dx\int (x+1) dx∫(x+1)dx.
x22+1+C\frac{x^2}{2} + 1 + C2x2+1+C
x2+x+Cx^2 + x + Cx2+x+C
x22+x+C\frac{x^2}{2} + x + C2x2+x+C
x2+Cx^2 + Cx2+C