Find n!n!n! recursively. n!n!n! is equal to:
n+(n−1)!n + (n-1)!n+(n−1)!
(n−1)!/n(n-1)! / n(n−1)!/n
nnn^nnn
ntimes(n−1)!n \\times (n-1)!ntimes(n−1)!