Find sin(2α)\sin(2\alpha)sin(2α) if cosα=−35\cos\alpha = -\frac{3}{5}cosα=−53 and α∈(π/2,π)\alpha \in (\pi/2, \pi)α∈(π/2,π).
2425\frac{24}{25}2524
−2425-\frac{24}{25}−2524
1225\frac{12}{25}2512
−1225-\frac{12}{25}−2512