Find tan(θ)\tan(\theta)tan(θ) if sin(θ)=12\sin(\theta) = \frac{1}{2}sin(θ)=21 and cos(θ)=−32\cos(\theta) = -\frac{\sqrt{3}}{2}cos(θ)=−23.
33\frac{\sqrt{3}}{3}33
−33-\frac{\sqrt{3}}{3}−33
−3-\sqrt{3}−3
3\sqrt{3}3