Find the area under f(x)=1x+1f(x) = \frac{1}{x+1}f(x)=x+11 from x=0x=0x=0 to x=2x=2x=2.
ln(3)\ln(3)ln(3)
ln(2)\ln(2)ln(2)
333
e3−1e^3 - 1e3−1