Find the average value of f(x)=exf(x) = e^xf(x)=ex on [0,2][0, 2][0,2].
e2−1e^2-1e2−1
eee
e2+12\frac{e^2+1}{2}2e2+1
e2−12\frac{e^2-1}{2}2e2−1