Find the condition for the point (h,k)(h, k)(h,k) to lie inside the circle x2+y2−4x+6y−8=0x^2 + y^2 - 4x + 6y - 8 = 0x2+y2−4x+6y−8=0.
h2+k2−4h+6k−8=0h^2 + k^2 - 4h + 6k - 8 = 0h2+k2−4h+6k−8=0
h2+k2−4h+6k−8>0h^2 + k^2 - 4h + 6k - 8 > 0h2+k2−4h+6k−8>0
h2+k2−4h+6k+8<0h^2 + k^2 - 4h + 6k + 8 < 0h2+k2−4h+6k+8<0
h2+k2−4h+6k−8<0h^2 + k^2 - 4h + 6k - 8 < 0h2+k2−4h+6k−8<0