Find the coordinates of the vertex of the parabola y=2(x+3)2−4y = 2(x+3)^2 - 4y=2(x+3)2−4.
(−3,−4)(-3, -4)(−3,−4)
(3,−4)(3, -4)(3,−4)
(−3,4)(-3, 4)(−3,4)
(3,4)(3, 4)(3,4)