Find the derivative of f(x)=xx2+1f(x) = \frac{x}{x^2+1}f(x)=x2+1x.
1−x2(x2+1)2\frac{1-x^2}{(x^2+1)^2}(x2+1)21−x2
1+x2(x2+1)2\frac{1+x^2}{(x^2+1)^2}(x2+1)21+x2
x2−1(x2+1)2\frac{x^2-1}{(x^2+1)^2}(x2+1)2x2−1
12x\frac{1}{2x}2x1