Find the derivative of f(x)=x1/xf(x) = x^{1/x}f(x)=x1/x for x>0x > 0x>0.
x1/x(1−lnxx2)x^{1/x} (\frac{1-\ln x}{x^2})x1/x(x21−lnx)
x1/x(lnx−1x2)x^{1/x} (\frac{\ln x - 1}{x^2})x1/x(x2lnx−1)
1xx1/x−1\frac{1}{x} x^{1/x - 1}x1x1/x−1
x1/xln(x)x^{1/x} \ln(x)x1/xln(x)