Find the derivative of f(x)=x4⋅ln(x2+1)f(x) = x^4 \cdot \ln(x^2 + 1)f(x)=x4⋅ln(x2+1).
4x3ln(x2+1)+2x5x2+14x^3 \ln(x^2 + 1) + \frac{2x^5}{x^2 + 1}4x3ln(x2+1)+x2+12x5
4x3ln(x2+1)+x4x2+14x^3 \ln(x^2 + 1) + \frac{x^4}{x^2 + 1}4x3ln(x2+1)+x2+1x4
x4⋅2xx2+1x^4 \cdot \frac{2x}{x^2+1}x4⋅x2+12x
4x3+2xx2+14x^3 + \frac{2x}{x^2+1}4x3+x2+12x