Find the derivative of f(x)=xlnxf(x) = x^{\ln x}f(x)=xlnx.
xlnxlnxx^{\ln x} \ln xxlnxlnx
xlnxlnxxx^{\ln x} \frac{\ln x}{x}xlnxxlnx
2xlnxlnx2 x^{\ln x} \ln x2xlnxlnx
2(lnx)xlnx−12(\ln x) x^{\ln x - 1}2(lnx)xlnx−1