Find the derivative of y=xx+1y = \frac{x}{x+1}y=x+1x using the quotient rule.
1(x+1)2\frac{1}{(x+1)^2}(x+1)21
x(x+1)2\frac{x}{(x+1)^2}(x+1)2x
1x+1\frac{1}{x+1}x+11
2x+1(x+1)2\frac{2x+1}{(x+1)^2}(x+1)22x+1