Find the derivative of y=x3−2x+5y = x^3 - 2x + 5y=x3−2x+5 and determine where y′=0y' = 0y′=0.
x=±23=±63x = \pm\sqrt{\frac{2}{3}} = \pm\frac{\sqrt{6}}{3}x=±32=±36
x=0x = 0x=0
x=±1x = \pm 1x=±1
x=±2x = \pm 2x=±2