Find the eccentricity of the hyperbola defined by the equation 25y2−16x2=40025y^2 - 16x^2 = 40025y2−16x2=400.
35\frac{3}{5}53
415\frac{\sqrt{41}}{5}541
414\frac{\sqrt{41}}{4}441
54\frac{5}{4}45