Find the equation of a line passing through (2,0)(2, 0)(2,0) and (0,−3)(0, -3)(0,−3).
x2−y3=1\frac{x}{2} - \frac{y}{3} = 12x−3y=1
x2+y−3=1\frac{x}{2} + \frac{y}{-3} = 12x+−3y=1
3x−2y=63x - 2y = 63x−2y=6
−3x+2y=−6-3x + 2y = -6−3x+2y=−6