Find the equation of the circle with diameter endpoints (−2,1)(-2, 1)(−2,1) and (4,−3)(4, -3)(4,−3).
(x+1)2+(y−1)2=13(x + 1)^2 + (y - 1)^2 = 13(x+1)2+(y−1)2=13
(x−1)2+(y+1)2=13(x - 1)^2 + (y + 1)^2 = 13(x−1)2+(y+1)2=13
(x−1)2+(y+1)2=52(x - 1)^2 + (y + 1)^2 = 52(x−1)2+(y+1)2=52
(x+1)2+(y−1)2=52(x + 1)^2 + (y - 1)^2 = 52(x+1)2+(y−1)2=52