Find the equation of the pair of straight lines represented by 6x2+xy−y2=06x^2 + xy - y^2 = 06x2+xy−y2=0.
(2x−y)(3x+y)=0(2x - y)(3x + y) = 0(2x−y)(3x+y)=0
(3x+y)(2x−y)=0(3x + y)(2x - y) = 0(3x+y)(2x−y)=0
(3x−y)(2x+y)=0(3x - y)(2x + y) = 0(3x−y)(2x+y)=0
(2x+y)(3x−y)=0(2x + y)(3x - y) = 0(2x+y)(3x−y)=0