Find the equation of the tangent plane to the sphere x2+y2+z2=3x^2 + y^2 + z^2 = 3x2+y2+z2=3 at the point (1,1,1)(1, 1, 1)(1,1,1).
x+y+z=3x + y + z = 3x+y+z=3
x+y+z=1x + y + z = 1x+y+z=1
x2+y2+z2=3x^2 + y^2 + z^2 = 3x2+y2+z2=3
2x+2y+2z=32x + 2y + 2z = 32x+2y+2z=3