Find the equilibrium solutions for y′=y3−4yy' = y^3 - 4yy′=y3−4y.
y=0,2y = 0, 2y=0,2
y=0,2,−2y = 0, 2, -2y=0,2,−2
y=4,−4y = 4, -4y=4,−4
y=2,−2y = 2, -2y=2,−2