Find the Euclidean norm of v=(3,−4,12)\mathbf{v} = (3, -4, 12)v=(3,−4,12) and identify the corresponding unit vector.
∣v∣=13|\mathbf{v}| = 13∣v∣=13 and the unit vector is 113(3,−4,12)\frac{1}{13}(3, -4, 12)131(3,−4,12)
∣v∣=19|\mathbf{v}| = 19∣v∣=19 and the unit vector is 119(3,−4,12)\frac{1}{19}(3, -4, 12)191(3,−4,12)
∣v∣=169|\mathbf{v}| = \sqrt{169}∣v∣=169 and the unit vector is (313,−413,1213)\left(\frac{3}{13}, -\frac{4}{13}, \frac{12}{13}\right)(133,−134,1312)
∣v∣=5|\mathbf{v}| = 5∣v∣=5 and the unit vector is 15(3,−4,12)\frac{1}{5}(3, -4, 12)51(3,−4,12)