Find the excluded values for g(x)=x2+1x3−4xg(x) = \dfrac{x^2 + 1}{x^3 - 4x}g(x)=x3−4xx2+1.
x=0,2,−2x = 0, 2, -2x=0,2,−2
x=0x = 0x=0 only
x=±2x = \pm 2x=±2
x=4x = 4x=4