Find the general solution for sin(x)=32\sin(x) = \frac{\sqrt{3}}{2}sin(x)=23 for xxx in radians.
x=π3+2kπx = \frac{\pi}{3} + 2k\pix=3π+2kπ or x=2π3+2kπx = \frac{2\pi}{3} + 2k\pix=32π+2kπ
x=π6+2kπx = \frac{\pi}{6} + 2k\pix=6π+2kπ
x=π3+kπx = \frac{\pi}{3} + k\pix=3π+kπ
x=2π3+2kπx = \frac{2\pi}{3} + 2k\pix=32π+2kπ