Find the general solution of the equation y′+y=exy3y' + y = e^x y^3y′+y=exy3.
y−2=2ex+Ce2xy^{-2} = 2e^x + Ce^{2x}y−2=2ex+Ce2x
y−2=Ce2x−exy^{-2} = Ce^{2x} - e^xy−2=Ce2x−ex
y−2=2ex+Ce−2xy^{-2} = 2e^x + Ce^{-2x}y−2=2ex+Ce−2x
y2=2ex+Ce2xy^{2} = 2e^x + Ce^{2x}y2=2ex+Ce2x