Find the general solution of y′′−y′−2y=0y'' - y' - 2y = 0y′′−y′−2y=0.
y=c1e−2x+c2exy = c_1e^{-2x} + c_2e^xy=c1e−2x+c2ex
y=c1ex+c2e−2xy = c_1e^{x} + c_2e^{-2x}y=c1ex+c2e−2x
y=c1e2x+c2e−xy = c_1e^{2x} + c_2e^{-x}y=c1e2x+c2e−x
y=c1ex+c2e2xy = c_1e^{x} + c_2e^{2x}y=c1ex+c2e2x