Find the general solution to the exact differential equation (2xy2+2)+(2x2y)y′=0(2xy^2 + 2) + (2x^2y)y' = 0(2xy2+2)+(2x2y)y′=0.
x2y2+x=Cx^2y^2 + x = Cx2y2+x=C
x2y2+2y=Cx^2y^2 + 2y = Cx2y2+2y=C
2x2y2+2x=C2x^2y^2 + 2x = C2x2y2+2x=C
x2y2+2x=Cx^2y^2 + 2x = Cx2y2+2x=C