Find the interval of convergence for ∑n=1∞(x−2)nn\sum_{n=1}^{\infty} \frac{(x-2)^n}{n}∑n=1∞n(x−2)n.
[1,3)[1, 3)[1,3)
(1,3](1, 3](1,3]
[1,3][1, 3][1,3]
(1,3)(1, 3)(1,3)