Find the inverse of f(x)=log3(x+x2+1)f(x) = \log_3(x + \sqrt{x^2 + 1})f(x)=log3(x+x2+1).
f−1(x)=3x−3−x2f^{-1}(x) = \frac{3^x - 3^{-x}}{2}f−1(x)=23x−3−x
f−1(x)=3x−3−xf^{-1}(x) = 3^x - 3^{-x}f−1(x)=3x−3−x
f−1(x)=3x+3−x2f^{-1}(x) = \frac{3^x + 3^{-x}}{2}f−1(x)=23x+3−x
f−1(x)=log3(x)f^{-1}(x) = \log_3(x)f−1(x)=log3(x)