Find the inverse of f(x)=x2+6x+5f(x) = x^2 + 6x + 5f(x)=x2+6x+5 for x≥−3x \geq -3x≥−3.
f−1(x)=−3+x+4f^{-1}(x) = -3 + \sqrt{x+4}f−1(x)=−3+x+4
f−1(x)=−3−x+4f^{-1}(x) = -3 - \sqrt{x+4}f−1(x)=−3−x+4
f−1(x)=3+x−4f^{-1}(x) = 3 + \sqrt{x-4}f−1(x)=3+x−4
f−1(x)=x+4−3f^{-1}(x) = \sqrt{x+4} - 3f−1(x)=x+4−3