Find the modulus of z=(2+3i)(1−i)4+2iz = \frac{(2 + 3i)(1 - i)}{4 + 2i}z=4+2i(2+3i)(1−i).
13/2\sqrt{13}/213/2
26/20\sqrt{26}/\sqrt{20}26/20
130/20\sqrt{130}/\sqrt{20}130/20
5/2\sqrt{5}/25/2